00:01
So in this problem, we're told that a heat lamp produces 32 .8 watts of power and has a wavelength of 6 .5 micrometers.
00:11
And so the first thing we'll do is convert these watts into joules seconds.
00:15
So joules over seconds is one watt.
00:18
So we have 32 .8 joules per second.
00:22
Now our 6 .5 micrometers is equal to our wavelength.
00:26
And so we will multiply that by 10 to the minus.
00:31
To convert it from micrometers into meters.
00:35
And so we have 6 .5 times 10 to the minus 6 meters for our wavelength.
00:40
Now that we have our wavelength, we can calculate a frequency c over lambda.
00:47
So the speed of light, 2 .998 times 10 to the 8 meters per second, divided by our wavelength, 6 .5 times 10 to the minus 6 meters.
00:58
And that gives us a frequency of 4 .61 times 10 to the 3rd...