In this problem, we are given that $\lambda=632.8 \mathrm{nm}$ and $\theta=20.5^{\circ}$. We want to find $d$.
Plugging in the given values into the formula, we have:
$$
d \sin (20.5^{\circ})=1 \cdot 632.8 \mathrm{nm}
$$
Now, we can solve for
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