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# A helium nucleus of mass $m=6.64 \times 10^{-27} \mathrm{kg}$ and charge $q=6.41 \times 10^{-19} \mathrm{C}$ is in a constant electric field of magnitude $E=2.00 \times 10^{-3} \mathrm{N} / \mathrm{C}$ pointing in the positive $x$ -direction. Neglecting other forces, calculate (a) the nucleus' acceleration and (b) its displacement after 3.00 $\mathrm{s}$ if it starts from rest.

## a. $1.93 \times 10^{5} \mathrm{m} / \mathrm{s}^{2}$b. 8.69 $\mathrm{m}$

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##### Andy C.

University of Michigan - Ann Arbor

LB
##### Marshall S.

University of Washington

### Video Transcript

Hello, Strains. Let's start or discussion. Suppose you haven't helium nucleus off Mass 6.64 into 10. This part minus 27. Cagey. Okay. And the charge on the nucleus is 6.41 in tow. 10 rece by minus 19 Coolum and applied electric fruit is in tow. Tenders par minus three Newton Park cooler. Now you have to find out the S oration generated on the nucleus. Okay, So basically are electrostatic force will be. Do we? This forces also caused two Emmy, so it will be acceleration. Will be Q B by i m no. By putting the values by putting these values, you will get the acceleration off 1.93 into Henry's Bar five. Meet a poor second square. No, you have to find out the displacement off the nucleus after he is because toe three second t close to three seconds and the initial velocity off the nucleus is Jiro. So basically, we have the question as it is a question. Beauty place half 80 square, Jules us you. So it will be won by two in tow. 1.93 into tennis par five into three square. So By solving this, you will get the answer off. 8.685 meter. Well, this is all for me for this video. I hope you will like the video. Thank you.

Other Schools
##### Andy C.

University of Michigan - Ann Arbor

LB
##### Marshall S.

University of Washington