00:01
As we know, the flow rate between stationary parallel plate can be written as q, which is equal to pi d cube, sorry, pi, it will be no, it will be, it will be, it will be, pi d, a q, multiplied by dl p, divided by 12 mu, 12 ,000, multiplied by l, let this is equation number 4.
00:32
Let's put all the variables value here we get.
00:35
Q is equal to 5 multiplied by the diameter.
00:38
The diameter is given as 6 x x per minus 3 meter.
00:41
6 multiplied by 10 per minus 3 meter multiplied by aq.
00:47
The value of age 2 multiplied by 10 to the power of minus 6 meter it will be q.
00:54
Multiply the pressure difference is given as 600 megaparcal, that is 6.
01:00
Multiplied by 10 to the power of 6, pascal divided by 2l multiplied by mu.
01:09
The value of mu at 35 degrees centigrade is 3 .8 multiplied by 10 to the power of minus 2 newton second per meter square.
01:21
This term multiplied by the value of l, capital l is 50 multiplied by 10 to the power of minus 3 meter.
01:29
So upon solving we get q is equal to 3 .97 multiplied by 10 to the power of minus 9 meter cube per second.
01:43
So this is the leakage rate...