A hockey puck has a mass of 0.115 kg and strikes the pole of the net at 37 m / s. It bounces off

step 1 So for part A, we want to find the impulse. We can find then that the impulse would be equal to

A hockey puck has a mass of 0.115 kg and strikes the pole of...

A hockey puck has a mass of $0.115 \mathrm{kg}$ and strikes the pole of the net at $37 \mathrm{m} / \mathrm{s}$. It bounces off in the opposite direction at $25 \mathrm{m} / \mathrm{s}$, as shown in Figure $9-17$ a. What is the impulse on the puck? b. If the collision takes $5.0 \times 10^{-4} \mathrm{s}$, what is the average force on the puck? (FIGURE CANT COPY)

A hockey puck has a mass of $0.115 \mathrm{kg}$ and strikes the pole of the net at $37 \mathrm{m} / \mathrm{s}$. It bounces off in the opposite direction at $25 \mathrm{m} / \mathrm{s}$, as shown in Figure $9-17$
a. What is the impulse on the puck?
b. If the collision takes $5.0 \times 10^{-4} \mathrm{s}$, what is the average force on the puck?
(FIGURE CANT COPY)

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Key Concepts

Momentum

Momentum is the product of an object's mass and its velocity, representing the quantity of motion the object possesses. As a vector quantity, momentum has both magnitude and direction, making it essential for analyzing motion in collisions and other dynamic interactions.

Impulse

Impulse quantifies the change in momentum of an object when a force is applied over a specified time interval. It is calculated as the product of the force and the time it acts, and it effectively connects the forces exerted on an object to the resulting change in its state of motion.

Impulse-Momentum Theorem

The impulse-momentum theorem states that the impulse applied to an object is equal to the change in its momentum. This theorem forms a crucial basis for analyzing collisions, providing a direct relationship between force, time, and the resulting change in velocity.

Average Force

Average force refers to the constant force that would produce the same impulse as the actual varying force over a given time period. It is determined by dividing the total impulse by the time interval during which the force is applied, allowing for simplified calculations in collision problems.

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