Our Discord hit 10K members! 🎉 Meet students and ask top educators your questions.Join Here!

Like

Report

WZ
Numerade Educator

Like

Report

Problem 54 Easy Difficulty

A hole of radius $r$ is bored through the center of a sphere of
radius $R > r .$ Find the volume of the remaining portion of
the sphere.

Answer

$$
V=\frac{4}{3} \pi\left(R^{2}-r^{2}\right)^{3 / 2}
$$

More Answers

Discussion

You must be signed in to discuss.

Video Transcript

{'transcript': "The problem is the whole of gliders are disbarred. There was a danger of a severe Riders capitalize Criticism. It's more Find us the wand. The alarms of remaining portion of the sphere. Look at the graph here. Different rotate. This reader about likes axes. Then we'LL got the remaining portion of the sphere. Now for each backs. The cross section is a washer in the riders is they'd go to smaller outer riders He's caught you, our squire. Once I squired you took this more Then the volume of the remaining portion if they caught you Hi. Hams into girl from cereal too. Here it is from zero to this point, this is haveto are square on a small school here we want to I'm from on the function is spirit If our squire minus x squared square minus small square Jax, you know we might die too, because first the re compute the volume Way to take the test heart about axis X axis, then the month plan too. This is a whole part. I want him well retained by rotating the whole part about X axis. So be it to to pie integral from zero to motive I squired by small square. I have to Ah, squire minus I square minus our Sawyer. Jax, This is equal to two high times. Ah, square minus a small square, too. Three O R. Two minus one third Ham's execute from zero to routine. A square minus. Our school of the panther is full pie or three times Ah, square one smaller square to three over too."}

WZ
Top Calculus 2 / BC Educators
Catherine R.

Missouri State University

Anna Marie V.

Campbell University

Heather Z.

Oregon State University

Kristen K.

University of Michigan - Ann Arbor