The moment of inertia $I$ of a square cross section is given by the formula $I = \frac{b^4}{12}$, where $b$ is the side dimension of the square cross section. Substituting $b = 0.07$ m, we get
\[I = \frac{(0.07)^4}{12} = 2 \times 10^{-6} \, \text{m}^4.\]
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