A horizontal disk with a moment of inertia $I_{1}$ is rotating freely at an angular speed of $\omega_{1}$ when a second, nonrotating disk with a moment of inertia $I_{2}$ is dropped on it (Fig. $10-11$ ). The two then rotate as a unit. Find the final angular speed. Ignore the central rod.
From the law of conservation of angular momentum,
$$\begin{array}{l}
\text { Angular momentum before }=\text { Angular momentum after }\\
I_{1} \omega_{1}+I_{2}(0)=l_{1} \omega+I_{2} \omega\\
\text { Solving this equation leads to } \quad \omega=\frac{l_{1} 4_{1}}{l_{1}+I_{2}}
\end{array}.$$