00:01
Okay, and this problem, there is a lot of geometry going on.
00:05
So take a look at this diagram, this very detailed diagram of what's going on.
00:11
So we have a light ray that goes into this glass prism, crown glass prism, and it is refracted within the prism, and then it is refracted again whenever that light ray gets back into the air.
00:24
So there are two different refractions happening.
00:26
And what we want to know is what is the angle of deviation here? so we're going to have to do a little bit of work to figure out these angles going into the prism, going out of the prism, and then what is that angle of deviation.
00:42
So to get started, let's figure out.
00:45
They tell us that this angle here, beta, is, i'm sorry, 30 degrees.
00:55
30 degrees.
00:56
So we want to figure out what these other angles are because the ray goes in parallel to the horizontal.
01:05
That means that this ray will produce an angle that is congruent to angle alpha.
01:17
So every triangle makes up 180 degrees.
01:25
So we will subtract the angle that is given to us.
01:30
And we know that there are two of those alpha angles.
01:33
So we're going to divide this by two.
01:35
And that tells us that each of those angles is 75 degrees.
01:39
So that's our start here.
01:40
75 degrees.
01:42
The angle of incidence is going to be the angle between the ray and the normal.
01:48
So we draw this normal here perpendicular to the surface of the triangle.
01:53
That's where prisms are unique.
01:54
We're not dealing with two parallel surfaces.
01:57
We're dealing with surfaces that are angled.
02:00
So to figure this out, we know that the normal produces a 90 degree angle.
02:05
So theta 1 can be found by taking 90 minus the alpha.
02:10
Angle, 75, and we know that theta 1 is 15 degrees.
02:16
Okay, something that i want to bring to your attention, because we'll come back to this later, is that over here, the normal is going to produce an angle of incidence similar to theta 1.
02:34
We'll come back to that a little bit later, but just right here, this normal and this h1 line will revisit later.
02:41
But there is an angle right there that is going to be useful to us.
02:49
All right.
02:50
Next, we want to use snell's law to figure out the angle of reflection.
02:56
So we use the index of refraction for error, sine theta 1, set it equal to index of reflection for glass.
03:06
And in this case, the crown glass index of refraction is 1 .52, sine theta, 2 .2.
03:14
We're going to solve for theta 2.
03:17
So we want to do the inverse sign.
03:22
Sign theta 1 divided by index of refraction for glass when we substitute our values.
03:30
I'm sorry, this is the inverse sign.
03:34
We get the inverse sign of 1 .0, sign 15 divided by 1 .52.
03:44
And that gives us a value for theta 2 of 9 .8 degrees.
03:53
Okay, so that's 9 .8 degrees relative to the normal.
03:59
Next step, we're going to solve for theta 3.
04:03
Remember, we need to solve for theta 3 because it's going into this surface right here at an angle...