Question

A horizontal, parallelsided plate of glass having a refractive index of 1.52 is in contact with the surface of water in a tank. A ray coming from above in air makes an angle of incidence of 35.0$^\circ$ with the normal to the top surface of the glass. (a) What angle does the ray refracted into the water make with the normal to the surface? (b) What is the dependence of this angle on the refractive index of the glass?

Name: Problem 12, Chapter 33: University Physics with Modern Physics
Uploaded: 2019-08-01T15:31:43-08:00
Duration: 1 min 23 s
Channel: Salamat Ali

   A horizontal, parallelsided plate of glass having a refractive index of 1.52 is in contact with the surface of water in a tank. A ray coming from above in air makes an angle of incidence of 35.0$^\circ$ with the normal to the top surface of the glass. (a) What angle does the ray refracted into the water make with the normal to the surface? (b) What is the dependence of this angle on the refractive index of the glass?

University Physics with Modern Physics

Hugh D. Young 14th Edition

Chapter 33, Problem 12

Instant Answer

Solved by Expert Salamat Ali

08/01/2019

Step 1

Mathematically, this is expressed as: $$n_1 \sin(\theta_1) = n_2 \sin(\theta_2)$$ where $n_1$ and $n_2$ are the refractive indices of the first and second medium, and $\theta_1$ and $\theta_2$ are the angles of incidence and refraction, respectively. Show more…

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A horizontal, parallelsided plate of glass having a refractive index of 1.52 is in contact with the surface of water in a tank. A ray coming from above in air makes an angle of incidence of 35.0$^\circ$ with the normal to the top surface of the glass. (a) What angle does the ray refracted into the water make with the normal to the surface? (b) What is the dependence of this angle on the refractive index of the glass?