00:01
In the given problem, suppose here this is the hot air balloon and this is the basket attached with it having some passengers in it.
00:20
Volume of the balloon is supposed represented as vb.
00:31
The density of hot air is represented as row, h .a, mass.
00:45
Of the passenger with basket that is m and density of air is suppose row a.
01:09
Now the mass of the basket along with the passenger will be giving this weight mg acting downward vertically downward the weight of this balloon that will also be acting vertically downward, which is given by the volume of this balloon means v b into the density of hot air inside it, row h .a into g.
01:41
And as the balloon is having no external, no net force acting on it, so as per arquodiz principle, the point force will be acting on it in upward and direction and that buoy force will be equal to the addition of these two forces acting vertically downward.
02:10
Hence we can say vb into row h a into g plus m g is equal to v b for point force that is the volume that is the weight of the air displaced so that will be volume of the balloon because the same equivalent amount of volume of air will be displaced by the balloon.
02:36
So this is vb, the volume of the air displaced into density of air into g.
02:43
Then this g can be taken as a common out.
02:46
So leaving behind vb into row h a plus m is equal to vb into row a into g.
02:57
So canceling this g from both the sides...