a-how-many-350-mathrmnm-uv-photons-are-needed-to-provide-a-total-energy-of-25-mathrmj-b-how-many-750

Question

(a) How many $350-\mathrm{nm}$ (UV) photons are needed to provide a total energy of 2.5 $\mathrm{J}$ (b) How many $750-\mathrm{nm}$ photons are
needed to provide the same energy?

Zulfiqar Ali · Accepted Answer

relevant off ultraviolet photons, uh, equals bad lint off ultraviolet photons equals Ahh. 350 nanometers. Refund fit 350 centimeters and it&#x27;s equal to 350. Multiply by 10 to the power minus nine meters since Nana is 10 to the power minus nine. Therefore we have lambda equals 3 50 Multiply by 10 to the power minus 19. Uh, mystery minus nine meters. Total energy don&#x27;t oh energy. Total energy equals 2.5 tools to 0.5 jewels and energy off a single foot on his Cuban by B equals H f An Edge f equals HC, divided by Lambda Frequency equals C derided by lambda. Therefore, we have energy equals and see divided by lambda No, let&#x27;s substitute values. Uh H is 6.63 Multiply by 10 to the power um minus 34 A multiply by multiplied by C, speed off light. It&#x27;s equal to three multiply by 10 to the power it divided by divided by lander a rebel and equals 3 50 Multiply by 10 to the power minus line meters and solving Ah, this we had energy associated with ah single ultraviolet put on equals 5.7 5.7 multiplied by 10 to the power minus 19. Jules, this is Ah, the energy off. Single ultraviolet foot on now. Number off. Ultraviolet photons needed to provide 2.5 jewels. Uh, equals So number off number. Oh, ultraviolet for dawn for tones needed to provide, uh May did to provide needed to provide 2.5 tools to 0.5 jewels equals 2.5, divided by 5.7 5.7 multiplied by 10 to the power minus 19. And this abuses this gives us for point for multiply by Anthony Power 18 foot owns 18 What? Tom? So number of ultraviolet photons needed to provide 2.5 jewels? Uh, is 4.4 multiplied by 10 to the power 18 for Tom&#x27;s. All right, and we have rebellin off red photons. Um, grab a lint off. Red photons revel in web lind off red photons. Red photons 750 millimeters 750 nano meters and in meters grab Lindy&#x27;s 7 50 Multiply by 10 to the power minus line meters and energy off our energy off a single red foot on energy entity Oh, a single energy off a single Redfoot on Red Fort on equals. Mmm. Equals H c. Divided by, uh, we have lend off. Red foot on on DDE. This can&#x27;t be regiones. Um, you know, let&#x27;s substitute values, which is 6.63 multiplied by 10 to the power minus 34 and C is pre multiply by 10 to the power eat divided by wetland is 750 Multiply by 10 to the power minus mine meters on. Therefore, we have energy e equals 2.7 multiplied a tentative hour minus 19 years 2.7 Multiply by 10 to the power minus 19. Jules eyes, the energy dissociated with single red foot on now Number of red for Don&#x27;s needed to produce 2.5 jewels equals number. Afraid for terms. Number off. Red photons number off. Red photons. Yeah, number off red four dawns. Uh, needed to produce nated, uh, to produce. Needed to produce. Um, 2.5 jewels. 2.5 jewels equals 2.5. Divided by 2.7. Multiplied by 10 to the power minus 19. Ah, 2.7. This is point, uh, 2.7 multiplied by 10 to the dollar minus 19 and this equals 9.3. Multiply by 9.3. Multiply by 10 to the power 19. Uh, sorry. Stand to the barber. 18 4 dawns 18 uh, four tones. So a number of French for Don&#x27;s needed to produce 2.5 jewels is a 9.3 multiplied identity power 18 uh for Don&#x27;s.

Eugene Schneider · Answer

his problem asks us to find the energy contained per one mole of photons with the following wavelength. So for letter, eh? We have zero point one five zero nano meters and we can convert that two meters by. There&#x27;s one meter for every ten to the Ninth Nano meters, so we can convert that into one point five times ten to the minus tenth meters. Now we can find the energy of a single photons by equals H c. Over lambda the wavelength h is planks constant six point six two, six times ten to the minus thirty fourth C is the speed of light. So that&#x27;s two point nine nine times ten to the eighth. And we divide that by our wavelength. We just found of one point five times ten to the minus tenth. And that gives us our energy perf otan to be one point three to six times ten to the minus fifteenth. So that&#x27;s Jules, her photons. But we don&#x27;t want jewels perform time. We want jewels. Prum. All. So to get Jules prom all we just multiply by avocados numbers six point two, two times ten to the twenty third. And that will give us our final answer of seven point nine eight times ten to the eighth and that&#x27;s Jules per mall, which is what we want. Now we do the same thing for a letter B. We start with Ah, two point one five times ten to the minus fifth Nano meters and we convert that the same way. So one meter over ten to the ninth and Anna meters, not Nana meters cancel and we get our wavelength in meters two point one five times ten to the minus fourteenth meters and we use that same formula equals H C over Lambda the wavelength to determine the energy of a single photons. So six point six two six times ten to the minus thirty fourth times the speed of light two point nine, nine times ten to the eighth and we divide that by our wavelength to point one five times ten to the minus fourteenth. And that gives us our energy per photons to be nine point two, two times ten to the minus twelfth Jules Perf Otan. So again we multiply that by Abu God rose number six point two, two times ten to the twenty third and we get our final answer to be five point five five times ten to the twelfth Jules Permal, and that is our final answer.

Ronald Prasad · Answer

let&#x27;s calculate the energy of one mole of photons for each of the following wavelengths. So the energy, one more of photons, it&#x27;s equal to avocado is number times The energy of one photon which is hc over lambda. So for a the energy is equal the avocados number. Yeah. And then this would be mhm 6626 to 10 to the negative 34 those per seconds speed of light. Yeah. Yeah. And yeah, 1500 nm, 1510009 -9 m. And this gives us, we&#x27;re going to assume three significant figures and This would be equal to 7.98 Tend to be 4th pupils per mole. The energy of one mole of photons for B r wavelength is visible light 500 nanometers. So the energy is equal to 6.23 times 10 to the 23 times 6.626 consider the negative 30 for jules per second, the speed of light. 3.2 times 10 to the eight m per 2nd. And 500 nanometers is 500 Times 10 to the -9 m. This gives us an energy of 2.39 Times tend to be 5th jewels per mole. And for CIA wavelength is in the ultraviolet region 150 nanometers energy here 6.2310 to the 23rd Times 6.626 times 10 to the -34. Mhm For 2nd Speed of Light. Yeah. And 150 nm is 150 times 10 to the -9 m. This gives us an energy of 7.98 times tend to be out there jules for more. Uh huh. Mhm.

Eugene Schneider · Answer

So this problem gives us the wave life of two different photons and wants us to find the energy contained in one mole of these photons. And so the first thing we&#x27;ll do is use the wavelength to find the frequency. And so are we have frequency new equal speed of light C over Lambda wavelength. And so we have the speed of light 2.998 times 10 to the eighth meters per second, divided by our wavelength, which is 0.135 nano meters. So multiply that by 10 to the minus ninth to convert it into meters. And that gives us a frequency of 2.22 times 10 to the 18th hurts. Now that we have that frequency, we can find the energy of a single photons by using the equation. E equals h knew and so ages planks Constant 6.626 times 10 to the negative 34th kilogram meters squared over seconds. Times are frequency 2.222 times 10 to the 18th hurts. And that gives us an energy of 1.47 times 10 to the negative 15th Jules. And this is the energy of one photons. So to find the energy of a mole of photons, we multiply by avocados. Number 6.222 times 10 to the 23rd. And that gives us an energy off. One mole of photons to be 8.86 times 10 to the eighth. Jules. And that&#x27;s your final answer for letter, eh? Now we&#x27;ll do the same thing for better be first we&#x27;ll find our frequency. So speed of light 2.998 times 10 to the eighth meters per second, divided by our wavelength which this time we have to 0.15 times 10 to the minus fifth Nana meters so again will multiply that by 10 to the minus tonight in order to get our answer in meters and that&#x27;ll give us a frequency of one point 39 times 10 to the 22nd hurts. So now that we have that, we can use our e equals h new equation. So planks constant 6.6226 times 10 to the negative 34th kilogram meters squared over seconds. Times are frequency 1.39 times 10 to the 22nd hurts and that gives us the energy of a single photons to be 9.224 times 10 to the negative 12th Jules and again when multiply that by Abu God Rose number to get the energy of a mole of photons, which in this case is 5.556 times 10 to the 12th Jules, and that will be our final answer.

Ze-Han Lee · Answer

All right, so in this problem, we know that Ah, frequency the frequency of the photo ihsaa to put times 10 to the 13th hurts. And so the energy off the photo has expression h time after we&#x27;re f a chaste upon constant. So this gives you a point. 0 83 electoral votes and in part B. Ah. So we want to know how many off many fortunes we need to win. It absorbs so that the tightly bonding molecules could be torn apart. So, uh, I just looked at your text book and I found that energy all the time. Bonding. A Montague has energy e t equal turn electoral votes in the so the number that we need thio break it apart is an equally t over t overheat. All right, so this gives you 1 20 and in part, see, suppose we are looking at a different photo. Whose frequencies? Ah ah, one start. It&#x27;s a three times 10 to the twenties hurts. So we can up to a new energy for this camera reform photo e equal h time that right. So this gives you 1.24 times 10 to the six electoral votes and, uh, Hardy. So we want to know how many molecules that we can use it to break apart. So again, the number of molecules that we can use is in equal, led by by E T A. So this equal 1.24 times 10 to the fifth Marcus monarchy is okay.

William Mills · Answer

this question begins with the description of the system, says the outermost electron oven. Adam has a binding energy of 2.5 electron volts. Different here is be. And then it says the Adam is exposed to light a high frequency high enough frequency to cause exactly one electron to be ejected and then says the ejected electron this time have a kinetic energy of two points here. Electron volts, This question asks. How much energy did photons of how much energy did photons of the incoming light contained? Once more, It tells us that the binding energy up that electron is 2.5, and after it&#x27;s been ejected, it has a kinetic energy of 2.0 all of this energy for the system. What it takes to kick it out, and what it has after it&#x27;s been kicked out has to come from the photons. So that photo must have had the energy that is the sum of both what it took to get it out and what it has after it&#x27;s been kicked out. Some of these two values is 4.5 electron volts, and that answer is given to us by Option C. the photo must have had 4.5 electron volts of energy in order to give US 2.0 or Turnbull&#x27;s, a kinetic energy of an electron that had 2.5 electron volts off by the energy.

Problem

(a) How many photons per second are emitted by a …

Problem 23 Medium Difficulty

(a) How many $350-\mathrm{nm}$ (UV) photons are needed to provide a total energy of 2.5 $\mathrm{J}$ (b) How many $750-\mathrm{nm}$ photons are
needed to provide the same energy?

Answer

a) $4.4 \times 10^{20}$ photons
b) $9.4 \times 10^{20}$ photons

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Christina K.

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a) $4.4 \times 10^{20}$ photonsb) $9.4 \times 10^{20}$ photons

Physics

Christina K.

Andy C.

Marshall S.

Farnaz M.

Wave Optics - Intro

Multiple Aperture Interference - Overview

James S. WalkerPhysics

Christina K.

Andy C.

Marshall S.

Farnaz M.

a) $4.4 \times 10^{20}$ photons
b) $9.4 \times 10^{20}$ photons

James S. Walker

Physics