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(a) How many excess electrons must be added to one plate and removed from the other to give a 5.00 $\mathrm{nF}$ parallel-plate capacitor 25.0$\mu \mathrm{J}$ of stored energy? (b) How could you modify the geometry of this capacitor to get it to store 50.0$\mu$ J of energy without changing the charge on its plates?

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Physics 101 Mechanics

Physics 102 Electricity and Magnetism

Chapter 18

Electric Potential and Capacitanc

Kinetic Energy

Potential Energy

Energy Conservation

Electric Charge and Electric Field

Gauss's Law

Electric Potential

Capacitance and Dielectrics

Cornell University

University of Michigan - Ann Arbor

Simon Fraser University

University of Winnipeg

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What is this question? What we have is that we have a parallel plate capacitor, and, um, we know its capacitors. See those fact and apparent and we want you know, how much charge we want to put onto each plate so that we can get a certain energy of 25 bye Cruel Farrant. So in order to do that, the first thing to do is to try to express the energy in terms of capacitance and the church. So we already know that energy, of course. Well, half CV square. And because I would not have visa what you just form of Egypt's of Q oversea and just give us well, half ofthe Q Square oversee, which can Zen be changed into Q equals squared times to see you. Okay, so from this expression, we will be able to find how much charge is needed on each plate in order for this off 59 of parent to capacity that you have energy. It is a total energy of 25 micro fire. It so is two times or 5.0 times 10 to the negative nine parent times 25 times 10 to the negative six uh, this service is his job. Char Okay. And this gives us, uh, to charge off five times 10 cheesy detective seven cooler and want, You know, Hadi electrons u to be put out, we should play to achieve this. So electricals is each in actual has a charge of 1.6 times 10 to the negative 19. Colin. So sis gives us three point what, two times 10 to 19 3 2 10 to 12. It actually second question asks us How do you want to modifies the geometry of this Considers so that it could a stored twice this much of energy without changes in charge. So against a formula is Q square over to see, So if we want you to go up, but we want the charge to be the same, What we want is we want the capacitance to become 1/2 its original value and is that the passages can be expressed. Iss absolute bought a poverty. So if we want thiss to be 1/2 what we could do is we can eser double separation or we can half supplied area

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