00:01
In this question, what we have is that we have a parallel plate capacitor, and we know it's capacitance.
00:10
C equals 5 nanofarent, and we want to know how much charge we want to put onto each plate so that we can get a certain energy of 25 micro -farrant.
00:23
So in order to do that, the first thing we need to do is to try to express the energy in terms of capacitance and the charge.
00:32
So we already know that energy equals 1 half of cv square.
00:37
And because we do not have v, so we want to transform v in terms of q over c, and this gives us one half of q square over c, which can then be changed into q equals square root times 2cu.
00:54
Okay, so from this expression, we will be able to find how much charge is needed on each plate in order for this 5 -9o -farmine capacitor to have an energy, a total energy of 25 micro -farrant.
01:11
So it's 2 times 5 .0 times 10 to the negative 9 fernet times 25 times 10 to the negative 6.
01:25
So sorry, this is jaw...