00:01
Okay, here for problem 48, we're given a solid insulated sphere, and we want to find first the number of electrons that must be uniformly distributed within this sphere, so that the electric field magnitude right outside the surface is 1 ,500 nons per kulam.
00:24
We're given the radius, and yes, the charge is uniformly distributed.
00:31
Given that, at any point outside of the sphere, we can model it just like a point charge.
00:40
So our electric field formula will just be, i'll use k for kulam's constant, q total over r squared, the magnitude of the electric field.
00:56
So basically here to find the number of electrons, then we'll just say our total charge q is some number of electrons times e, where e is the charge of a single electron.
01:08
So we can set this up and use this value and use that we know what r is, and we can solve for n.
01:17
So if we do that, setting it up, we have e equals k and e over all right, big r squared, solving for n.
01:28
Then we have r squared times e times the magnitude of the electric fields over k times little e, the charge.
01:37
And if we plug all of our values in, remembering to convert this radius to, so, 2 .6 times 10 to the negative 1 power meters.
01:56
So just multiply this by 10 to the negative 2.
02:01
Doing this, then we can plug this in and we get that this is approximately 7 .04 times 10 to the 10th electrons is our number of electrons...