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(a) How many scconds are there in 1.00 year? (b) How many nanoseconds are there in 1.00 year? (c) How many years are there in 1.00 second?

A) $3.16 \times 10^{7} s$B) $3.16 \times 10^{16} n s$C) $3.17 \times 10^{-8}$ years

Physics 101 Mechanics

Chapter 1

Introduction, Measurement, Estimating

Physics Basics

Cornell University

Simon Fraser University

University of Winnipeg

Lectures

04:16

In mathematics, a proof is a sequence of statements given to explain how a conclusion is derived from premises known or assumed to be true. The proof attempts to demonstrate that the conclusion is a logical consequence of the premises, and is one of the most important goals of mathematics.

09:56

In mathematics, algebra is one of the broad parts of mathematics, together with number theory, geometry and analysis. In its most general form, algebra is the study of mathematical symbols and the rules for manipulating these symbols; it is a unifying thread of almost all of mathematics.

02:29

(a) How many seconds are t…

01:50

a) How many seconds are th…

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(II) ($a$) How many second…

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00:43

How many seconds are there…

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One year is approximately …

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$$ \begin{array}{l}{\text …

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(II) A light-year is the d…

A light-year is the dista…

00:52

Perform the indicated calc…

04:17

02:18

(II) A $\textbf{light-year…

so for party, we want how many seconds in a year. So we have 1.0 years. This will equal 1.0 years will multiply this by three points. You can say 365 days for one year, 24 hours for one day, and we can multiply this by 3600 seconds for one hour. And this is equaling 3.156 times 10 to the seventh seconds per year. Um, for part B, we want to find how many nanoseconds and one year. So we know that there are 3.156 times 10 to the seventh seconds per year. And then for every, um, one second, there are 10 to the ninth nanoseconds for every one second. Therefore, there are 3.156 times, 10 to the 16th nanoseconds per year. And then for part C, we want to find how many years in one second. So here it would simply be equal to ah one second divided by 3.1556 times 10 to the seventh, um, seconds per year. So essentially there are going to be 3.153 point we can round 3.17 times, 10 to the negative eighth years per second. That is the end of the solution. Thank you for watching.

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