Question
a. How much energy is needed to ionize a hydrogen atom that is initially in its $n=4$ state?b. In what region of the electromagnetic spectrum does this photon fall? If it is in the visible portion of the spectrum, what color does this photon correspond to?
Step 1
The formula for the energy of a hydrogen atom is given by $E_n = -13.6 \, \text{eV} / n^2$. Substituting $n=4$ into this equation, we get: \[E_4 = -13.6 \, \text{eV} / 4^2 = -0.85 \, \text{eV}\] Show more…
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$\bullet$ (a) How much energy is needed to ionize a hydrogen atom that is in the $n=4$ state? (b) What would be the wavelength of a photon emitted by a hydrogen atom in a transition from the $n=4$ state to the $n=2$ state?
1. A hydrogen atom emits a photon at 656 nm. a) What is the energy (in J) of this photon? b) If this emission corresponds to an electron falling to the n=2 level, from which energy level did it originate? c) In what region of the electromagnetic spectrum does this fall?
A hydrogen atom is in the $n=2$ state. (a) How much energy is required to remove the electron completely from the atom? (b) What's the wavelength of a photon with this energy?
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