Problem

Two point charges exert a 5.00 $\mathrm{N}$ force…

01:28

Problem 25 Medium Difficulty

(a) How strong is the attractive force between a glass rod with a 0.700$\mu \mathrm{C}$ charge and a silk cloth with a $-0.600 \mu \mathrm{C}$ charge, which are 12.0 $\mathrm{cm}$ apart, using the approximation that they act like point charges? (b) Discuss how the answer to this problem might be affected if the charges are distributed over some area and do not act like point charges.

Answer

a)
0.26 $\mathrm{N}$
b)
Integrate over two regions infinitesimal contributions of the Coulomb force

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Physics 102 Electricity and Magnetism

College Physics for AP® Courses

Chapter 18

Electric Charge and Electric Field

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Video Transcript

Welcome back to new around. My name is Kevin Chirac. So here we have a situation where we have two different charges, each with different sizes, and there it's certain radius apart, and we're being asked to consider that these are just point charges and calculate the force between them. When we know the equation for the forced, the electric force is going to K Times Q. One times Q two over our square since K is 8.9 times 10 to the ninth are two. Charges are going to be no 20.7 times 10 to the negative six times 0.6 times 10 to the negative six and noticed that I'm not including that signs of those charges because I'm going to be tabulated the forces a vector and the senses are opposite charges. It's just going to be a positive force. Of course, that's going to be attracting in this just depends on whatever way you decide to set up your scenario, where ever use that you're important system and the radius is going to be 0.12 square 0.12 meters or 12 centimeters squared. If you throw all this in your character. What you're going to get is that this becomes a total horse value of 0.26 mutants next time. Now, if these were larger reason, regions notice that this would be changed quite a bit. So you could imagine that we have this. What was it was a cough. It's still cloth and a glass rod so that we had a glass rod s o clock. And each of these were not point charges. But in fact, instead, at this charge distribution, we're not going to be able Teoh there, let's say the distance between their centers was this this 0.12 meters or maybe it's the closest distance. Either way, we're gonna have a number of charges that are quite a bit further away on the outside and thus were not going to be able Teoh, get all of the is the same radius of 0.12 meters. If we had chemical is on our side. What we could consider is actually just doing an integral or considering what each infant testimony, a small charge, the effect that that has on each contestant small charge in this glass rod. And then we were just at all of those contestants small charges together. But without the aid of calculus, this would be way too difficult of a problem. So enjoy this video if you did.

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