00:01
For part a, this would be the force diagram here.
00:02
This would be a quick sketch.
00:04
For part b, then we want to find the tension force, the magnitude.
00:09
We know that if x is here, x is equaling 1 .00 meters.
00:13
So we can then say that some of the forces, or some of the torts rather, in the left end would be equaling zero.
00:23
And this would equal negative 700 newtons multiplied by 1 .00 meters.
00:30
And then minus 200 newtons multiplied by 3 .00 meters minus and then 80 .0 neutins multiplied by 6 .00 meters and finally plus t sign of 60 degrees multiplied by 6 .00 meters.
00:58
So as you can see we can find t very easily.
01:01
Move all these to the other side.
01:03
Divide by 6 .00 meters, and we find that t is equalling 343 newton.
01:10
So after moving them all to the other side, dividing by 6 .00 meters multiplied by sign of 60, the magnitude of the tension force is 343 neutins.
01:22
Now, we can say that the sum of the forces in the x direction, applying newton's second law, is zero...