00:01
So here we know that delta y from the arrow to the target is zero meters.
00:05
So we can use the range equation.
00:07
We know that delta x is going to be equal to 38 .0 meters.
00:14
And this can also be equal to r.
00:17
We also know the vx initial, which equals vx final, is going to be equal to 23 .1 meters per second.
00:27
Again, there isn't any acceleration in the x direction.
00:31
So the time in the air is needed.
00:35
So time equals delta x divided by vx.
00:40
So this will be 38 .0 meters divided by 23 .1 meters per second.
00:47
And we're getting that t equals 1 .645 seconds.
00:52
1 .645 seconds.
00:56
Now we need to find the drop.
01:00
So y final equals y initial.
01:02
Plus v .y initial t plus 1 over 2 gt squared.
01:08
We know that v .y initial is zero.
01:10
We know that y initial is zero.
01:12
So we can simply say one half of 9 .8, 1 .645.
01:22
Oh, sorry...