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A hurricane-force wind of 200 $\mathrm{km} / \mathrm{h}$ blows across the faceof a storefront window. Estimate the force on the 2.0 $\mathrm{m} \times 3.0 \mathrm{m}$ window due to the difference in air pressureinside and outside the window. Assume the store is airtight sothe inside pressure remains at 1.0 atm. (This is why you shouldnot tightly seal a building in preparation for a hurricane).

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$1.2 \times 10^{4} \mathrm{N}$

Physics 101 Mechanics

Chapter 13

Fluids

Fluid Mechanics

University of Washington

Simon Fraser University

Hope College

University of Winnipeg

Lectures

03:45

In physics, a fluid is a substance that continually deforms (flows) under an applied shear stress. Fluids are a subset of the phases of matter and include liquids, gases, plasmas and, to some extent, plastic solids.

09:49

A fluid is a substance that continually deforms (flows) under an applied shear stress. Fluids are a subset of the phases of matter and include liquids, gases and plasmas. Fluids display properties such as flow, pressure, and tension, which can be described with a fluid model. For example, liquids form a surface which exerts a force on other objects in contact with it, and is the basis for the forces of capillarity and cohesion. Fluids are a continuum (or "continuous" in some sense) which means that they cannot be strictly separated into separate pieces. However, there are theoretical limits to the divisibility of fluids. Fluids are in contrast to solids, which are able to sustain a shear stress with no tendency to continue deforming.

04:13

A hurricane-force wind of …

02:07

Atmospheric pressure is ab…

03:17

The force of wind blowing …

02:42

02:25

01:11

Consider an airplane windo…

01:22

Force of the Wind on a Win…

so we want to find the force of the air. And so we're going to apply Bernoulli's equation. We know that pressure inside, plus 1/2 times row, the inside squared plus row G. Why inside would be equaling to the pressure outside, plus 1/2 times Roe v outside squared plus row G. Why outside Now we, ah, are going to say that the velocity on the inside of the window is essentially negligible. And so we can say that the pressure inside, minus the pressure outside or the change in pressure would be equaling 1/2 times the density of air multiplied by the velocity outside of the hurricane squared. This would be equaling the force of the air divided by the surface area of the roof. And so we can say that then the force of the air would be equaling 1/2 times the density of air times the velocity outside squared times, the area of the roof and so we can solve. So the force of the air would then be equaling 1/2 times 1.29 kilograms hurt cubic meter. This would be multiplied by 200 kilometers per hour, multiplied by one meter per second, divided by 3.6 kilometers per hour. This entire quantity would be squared. And then times the area of the roof we know to be 6.0 meters squared. And so the force of the air is found to be approximately equal to 1.2 times 10 to the fourth Newton's. This would be our final answer. That is the end of the solution. Thank you.

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