00:01
In this problem, we're given the formula c5h10, and we need to draw six isomers.
00:08
So to do this, i'm just going to start with a hexane chain and rearrange things.
00:22
I actually don't want that end one.
00:24
Okay, so first we're going to put a double bond on this first carbon, and we can name this one hexene.
00:33
I'm pretty sure you can also just call this hexine, but...
00:37
So the second one, i'm going to put a double bond in the middle.
00:40
So this is on the second and third carbon.
00:43
And it is a trans bond because the attached groups oppose each other on the double bond.
00:52
So this is trans two hexene.
01:00
And then i'm going to make a cis version of this.
01:03
So i'm going to make like this.
01:07
And this is cis two hexane.
01:14
So now i'm going to move around some of these groups and form some methyl.
01:20
So i'm going to move on to a butane structure...