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A hydrogen atom initially in its ground state $(n=1)$ absorbs a photon and ends up in the state for which $n=3 .$ (a) What is the energy of the absorbed photon?

(b) If the atom returns to the ground state, what photon energies could the atom emit?

a. $E_{31}=12.1 \mathrm{eV}$

b. $1.89 \mathrm{eV}$ and $10.2 \mathrm{eV}$

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we have one of our lambda. It was our times. 1/1 square miles, 1/3 squared. It was 8/9 are. So from here, we can find that Amanda it was 9/8 are putting the value of far. You will find that to be one or 2.5 Nana meter. Now, energy of the fortune will be given by a C O ver lander and for this wears. Then we find the energy to be 1.93 times tend to them than it is 18 June equals that times one e V over 1.6 times 10 to the native, 19 jewels equals who has electron voltage. Now we know that you want equals negative Started born six easy So e do with me You want over four equals negative Three born four easy and e three will be he wants over nine equals 91.51 easy. So from three to transition we will have 1.89 evey emission from 3 to 1 we would have Who else? 0.9 evey emission And from one to do you have 10 going toe e v admission. So this is the most suitable transition

Indian Institute of Technology Kharagpur

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