00:01
Here's the solution for the anova test for the mean cost of batteries given on, based on a variation of sizes.
00:12
So the null hypothesis is that the means are equal.
00:16
The mean prices are equal.
00:17
So mu1 equals mu2 equals mu3.
00:19
And then the alternative is that not all of them are equal.
00:23
And actually this is, this should be mu one, just to keep the same thing going.
00:29
On some mu1, mu2, and you three.
00:32
Okay, and the next step is to find the critical value, f star.
00:35
Now you can find that using a table, or you can, i build a program in the calculator, so that's the way i'm gonna show you, but you can certainly use a table.
00:42
It's probably either in your book, or you can probably just find it online, but i call it f star, and you need an alpha value, and that's given in your problem, the alpha's 0 .05.
00:52
The degrees of freedom in this case is two, because it's separated into three different categories, and it's always the number of categories minus one.
00:58
So three minus one is two.
00:59
And then the degrees of freedom for the denominator is 14.
01:02
That's the total number of data values minus the number of categories.
01:05
So there are 17 data values minus the three categories of 14.
01:09
Okay, so then that's the information and that you can use the table or you can build this...