00:01
In this problem, we will be scattering the phase line and the solution curve to this differential equation.
00:06
First, we must find the equilibrium points, and we find those wherever y -fram is equal to zero.
00:15
So if i factor, we have y times y minus 2 equals 0.
00:22
That gives us equilibrium points at y equals 0 and y equals 2.
00:34
To determine whether they're stable or unstable, okay, when y is less than zero, the derivative is positive, so that will tend towards zero.
00:54
Between zero and two, the derivative is negative, so that would tend to the left.
01:02
And greater than two, the derivative is positive, so that will tend to the right and go off to infinity.
01:08
So by observation we can see zero is a stable solution, but y equals to is unstable.
01:27
Now to create the phase nine, let's just add the information from part a.
01:36
Okay, the derivative was less than zero.
01:47
Now we want to add the information for the second derivative...