Enroll in one of our FREE online STEM summer camps. Space is limited so join now!View Summer Courses

Georgia Southern University

Problem 1
Problem 2
Problem 3
Problem 4
Problem 5
Problem 6
Problem 7
Problem 8
Problem 9
Problem 10
Problem 11
Problem 12
Problem 13
Problem 14
Problem 15
Problem 16
Problem 17
Problem 18
Problem 19
Problem 20
Problem 21
Problem 22
Problem 23
Problem 24
Problem 25
Problem 26
Problem 27
Problem 28
Problem 29
Problem 30
Problem 31
Problem 32
Problem 33
Problem 34
Problem 35
Problem 36
Problem 37
Problem 38
Problem 39
Problem 40
Problem 41
Problem 42
Problem 43
Problem 44
Problem 45
Problem 46
Problem 47
Problem 48
Problem 49
Problem 50
Problem 51
Problem 52
Problem 53
Problem 54
Problem 55
Problem 56
Problem 57
Problem 58
Problem 59
Problem 60
Problem 61
Problem 62
Problem 63
Problem 64
Problem 65
Problem 66
Problem 67
Problem 68
Problem 69
Problem 70
Problem 71
Problem 72

Need more help? Fill out this quick form to get professional live tutoring.

Get live tutoring
Problem 42

a. Identify the function's local extreme values in the given domain, and say where they occur.

b. Which of the extreme values, if any, are absolute?

c. Support your findings with a graphing calculator or computer grapher.

$$

f(x)=(x+1)^{2}, \quad-\infty<x \leq 0

$$

Answer

See the graph

You must be logged in to like a video.

You must be logged in to bookmark a video.

## Discussion

## Video Transcript

All right. So we have this function in f backs equals x X one squared in the domain and divinity Synnex listening to zero. So let's take the derivative to find our critical points. It's going to be two times X plus one. So have primal be zero when X equals negative one of a critical point and negative one. So first. So let's just go ahead and plot are critical point test half prime Well, to the left of negative one. Well, the negative into the right will be positive. So we have a and then we of course, we want to stop at zero because that's where our domain stops and so dysfunction is decreasing and then increasing up zero. And so we have a local max. So a local men and I have one Republican negative one that gives us zero. So the negative one zero local men And then if we consider this end point over here a local max, we have ah, local max it zero one. The men is going to be absolute to the absolute men. His name is one because it's the vertex of the Para Ebola. There's going to be no absolute Max because the function is going off to infinity. His ex goes to minus infinity

## Recommended Questions