00:03
Alright, so in this problem we have the circuit like this so we have this this cluster here and the other one and last one is for here and we have two point external point this is point this is point a this is point b and this is point d so this is c sorry this has a capacity c this is 2c 6 c and 4 c so for part a we want to find out the equivalent capacitance for the two point a and b, cab.
00:41
So for the cab, we can see that this 6c is actually in series of this 4c, right? so the equivalence of them will be equal to 4 times 6 over 4 plus 6, which is 2 .4 c times c.
01:03
And this 2c is actually in parallel with this two part.
01:09
So the equivalent capacitance of this 3 will be equal to 2c plus this 1, 2 .4c, which is 4 .4c.
01:22
And then this c is actually in series with this whole thing, right? so this will be 4 .4 times 1 divided by 4 .4 plus 1 times c.
01:36
So we can see that this actually is equal to cab.
01:42
So this value is 41 microferrales.
01:49
By the way, yeah, c is 50 microferrales.
01:55
And for part b, we want to find out c ad...