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Problem 39 Hard Difficulty
(a) If $ f(x) = e^x/ (2x^2 + x + 1), $ find $ f' (x). $
(b) Check to see that your answers to part (a) are reasonable by comparing the graphs of $ f, f', $ and $ f". $
Answer
(a) $f^{\prime}(x)=\frac{4 x}{\left(x^{2}+1\right)^{2}}$
$f^{\prime \prime}(x)=\frac{4\left(1-3 x^{2}\right)}{\left(x^{2}+1\right)^{3}}$
(b) See solution
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Top Calculus 1 / AB Educators
Heather Z.
Oregon State University
Caleb E.
Baylor University
Samuel H.
University of Nottingham
Joseph L.
Boston College
Watch More Solved Questions in Chapter 3
Video Transcript
he It's clears the when you read here. So you have up of X is equal to X square minus one over X square plus one. We're gonna use a quotient role. To find our derivative, we get X square plus one D over deep rex of X square minus one minus X square minus one D over DX of X square plus one all over X square plus one square has becomes equal to X square plus one arms to X minus X square minus one times two x over X square plus one square. This becomes equal to four X over X squared, plus one square. Now we're gonna apply the same rule to find the second derivative when we get X Square plus one square D over D X for X minus for X times D over DX for X square plus one square all over X square plus one square and you score that again and then this simplifies into four minus 12 X square over X square plus one cubed. Here you apply the chain rule. Now we're going to draw some graphs for part B. We're going to start with R F of X so we'll draw down in black, an uncle like this, and our red is gonna be our derivative first derivative, and then our second derivative is gonna be in green.
Top Calculus 1 / AB Educators
Heather Z.
Oregon State University
Caleb E.
Baylor University
Samuel H.
University of Nottingham
Joseph L.
Boston College
