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Numerade Educator

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Problem 27 Easy Difficulty

(a) If $ f(x) = $ sec $ x, $ find $ f'(x). $
(b) Check to see that your answer to part (a) is reasonable by graphing both $ f $ and $ f' $ for $ \mid {x} \mid < \pi/2. $

Answer

(a) $f^{\prime}(x)=\sec x \tan x$
(b)

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Video Transcript

it's clear. So when you raid here so we have f of X this equal to seek it backs minus. It's We're gonna find our derivatives. So we get leader of it. Is this equal to D over DX? You're seeking my Nestea over the ex for X Mrs Equal to seek it Times tangent minus one So that surgery of it is and we're gonna know draw our ground. This is pie hands Negative pie, huh? So our original graph will look like this, then our derivative ground. It's going to look like this.