00:01
So, given in problem number 76 that my spaceship, let us name it as spaceship a and another spaceship that is spaceship b are moving relative to each other.
00:19
Spaceship or the speed of a with respect to an observer on earth is v a e that is 0 .900 c and speed of b with respect to earth with respect to a is v b a that is 0 .500 c.
00:37
In problem 76 it has been asked to find the speed of spaceship b with respect to earth which were the answer to the problem was v b e that is 0 .966 c.
00:51
In the present problem which is in continuation with problem 76 it has been mentioned or given the length of the ship b for ship a is 24 meters.
01:08
It has been asked to find the length of ship b as measured by an observer in ship b by an observer on ship on earth.
01:23
If a rod of length l naught that is 24 meters is in my ship a what would be its length for an observer in on earth and third part what would be the length of the rod for an observer in or on ship b.
01:50
So coming to the first part of the question let the length of ship b for an observer in the ship b be l naught then using the concept of length contraction in the moving frame that is ship a we can write l naught is equals to l gamma where gamma is 1 by under root 1 minus the relative speed between b and a that is v b a square by c square.
02:31
So l naught that is the length of the ship b with respect to an observer in ship b will be determined by putting the values of l and v b a that comes out to be 24 by 0 .866 that is 27 .71 meters...