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Output voltage is normally distributed with standard deviation .25 volts, and the manufacturer wishes to test the null hypothesis h0 -mu equals 5 volts against the alternative is not equal 5 using a sample size n.
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We wish to calculate the type 2 error probability if the true mean output is 5 .05 volts, and we have the following data a and b.
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This question is testing our understanding of the language hypothesis testing, and how to calculate beta a type 2 error probability.
00:25
So first, an a to answer, we have to determine the boundary of our critical region, that is the boundary that determines whether or not we accept or reject our null hypothesis.
00:33
For alf equals 0 .05, and this being a two -tailed test, we must have that the pz greater than z -not equals pz less than negative z -not equals alpha over 2.
00:41
This gives z -not plus or minus 1 over 1 .96.
00:44
Thus, our critical boundary regions are, plugging in mu equals 5 from our test, 4 .85 and 5 .15, given the formula here.
00:51
Thus, the probability of beta is the probability x falls between these values...