The equation is given in terms of wavelength $\lambda$, but the hint is given in terms of $u$. So, we need to make a substitution. Let's set $u = \frac{hc}{\lambda kT}$, then $du = -\frac{hc}{\lambda^2 kT} d\lambda$. We can solve for $d\lambda$ to get $d\lambda =
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