00:02
Okay, let's consider isomers which are molecules with the same elemental composition but a different atomic arrangement.
00:09
We've got three isomers are shown here.
00:17
Um, okay, my isomers are cis 2 -butene and i'm just going to draw a simplified version.
00:38
This doesn't look right.
00:59
Our trans 2 -butene, which will be very similar but, and our 1 -butene, which will be c.
01:52
Okay, so now what are we doing? we are going to first, make this a little smaller, draw an energy level diagram relating energy content of the three isomers to energy content of combustion products, co2 and h2o.
03:03
And they want me to use l.
03:07
Okay, let's see if we can figure out how to do that.
03:34
So we have our 1 -butene was the highest, then our cis -butene, and then our trans 2 -butene was next.
04:04
So this will be 1 -butene plus 6 -o2, and our delta h for this one is negative 2716 .8 kilojoules per mole.
04:30
Here we have cis -butene plus 6 -o2g, and our delta h is 2709 .8 kilojoules per mole.
04:56
And finally, my trans -butene plus 6 -o2, and our delta h for this one is negative 2706 .6 kilojoules per mole.
05:16
And these will all go down to 4 -o2, whoops, 4 -co2 plus 4 -h2o -l.
05:36
So i think that's all they want there.
05:38
I'm not doing anything to scale.
05:41
Now let's see what they want next.
05:43
So this will next be used to calculate the enthalpy of formation for each isomer.
06:44
Okay, this will be pretty easy because a lot of them are the same here.
06:52
Okay, so delta h of formation for co2g is negative 393 .509, and i'll take that times 6, and that will equal negative 393 .509 times 6.
07:21
This is negative 2361 .054.
07:26
Oh, by 4.
07:28
I'm sorry, by 4.
07:38
Negative 393 .509 times 4.
07:47
This is negative 1574 .36 kilojoules...