Problem

Standing at the base of one of the cliffs of Mt. …

02:22

Problem 50 Hard Difficulty

A kangaroo can jump over an object 2.50 m high. (a) Calculate its vertical speed when it leaves the ground. (b) How long is it in the air?

Answer

(a) $v_{0}=7 \mathrm{m} / \mathrm{s}$
(b) $t=0.714 \mathrm{s}$

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Physics 101 Mechanics

College Physics for AP® Courses

Chapter 2

Kinematics

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Video Transcript

so the kangaroo can jump to a wife final equaling 2.50 meters. And this is happens to be wine, Max. Ah, we're at Why, Max? The final velocity is zero and so we can use the kinetic equation. V y Final squared equals V. Why initial squared? Plus two times the acceleration, the Y direction times Delta. Why? And so we can say that, then the initial velocity in the wind direction would be equal in the square root of two g delta. Why? And so this would be equaling the square root of two times 9.80 meters per second squared again. The negatives will, of course, cancel out and then most played by 2.50 meters. And so this is giving us approximately seven meters per second. At this point, we can say that this would be our V y initial other Let's keep the same script sub scripts. So the severe V y initial that is the speed with which the kangaroo leaves the ground and then we can say the time it takes to get there. Um, we could say that V Why finally equals V. Why initial plus g t. And we find that tea is simply equaling in this case, Negative V. Why initial divided by we can say negative G The negatives, of course. Cancel out. So this would be 7.0 meters per second, divided by 9.80 meters per second squared and tease equaling point 714 seconds. This would be our answer for, uh, for the second part. Rather, this is rather this would be a party and part B. That is the end of the solution. Thank you.

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