a-kevin-said-that-if-the-index-of-a-radical-is-even-and-the-radicand-is-positive-then-the-radical-ha

Question

a. Kevin said that if the index of a radical is even and the radicand is positive, then the radical has two real roots. Do you agree with Kevin? Explain why or why not.
b. Kevin said that if the index of a radical is odd, then the radical has one real root and that the root is positive if the radicand is positive and negative if the radicand is negative. Do you agree with Kevin? Explain why or why not.

James Kiss · Accepted Answer

Kevin says that if the index of a radicals, even in the Radicals, positive that we get to solutions, And for that we say Kevin is absolutely correct. Okay, here&#x27;s why Kevin is correct on this with RN Through of K, we get to solutions. Here&#x27;s a real example. If N is even like to in case positive, like nine, we have the square root of nine, and we know that the square root of nine is either. Three. You&#x27;re negative three for part B. Uh, coming says that if the Radic, if the index is odd in the radical, has a Onley one real root. And for this we should say that Kevin is correct again. Here&#x27;s an example. Why again, with the end through of K in this instance, either we have one route either a positive or a negative root. Let&#x27;s take an example of the cube root of eight. So N is odd, and K is positive. The cube root of eight is positive, too, whereas if K is negative, like the Cuba of negative eight that is equal to negative two. So we get only one solution. It depends on if K is positive or K is negative

M S · Answer

So Jennifer said that the fourth Roots, uh, a squared is the square root of a Do we disagree or agree? I agree, and I&#x27;ll show you what. So whenever you have the square root of a number will stay. In this case, there&#x27;s always been understood to here, and everything has an explanation. Boy. Already. So we want to write this with the fractional exponents will have a to the wood half. So another way to write our left hand side would have before three to base. We&#x27;re no other way to write this with Braxton. Explain it will have a report. Did you tell you the number under the house and put it over the number outside of the house. And to reduce that fraction, we&#x27;ll have a to the 1/2. And to rewrite that with a square root will help the square root of a and it is our right hand side. So we I agree

Dilip Paruchuri · Answer

Okay, guys. So in this problem, we&#x27;re we&#x27;re told the viewpoint of a student named Sarah and Sarah says that square with a is the only equal factor of the value. A and A is said to be an element of the real number, so just a real value. And she says that a square A is the equal factor of its meaning. A is equal to square with a type square with a squared A divides a evenly. Basically, that&#x27;s what she&#x27;s saying. And she says that this is true for thung values of A and the textbook. The problem asked us to say, Do we agree with this dude? What or don&#x27;t we? And it says If we do agree with that, say which values of A that this is true for and a key freezing. This problem is for some values obey because this some values of a could also be for all values A for non values of a or for some values obey. So let&#x27;s take a moment to understand what it means for some values today for some values of a means that some values work. Some bodies don&#x27;t obviously, but so let&#x27;s take a look at why it&#x27;s not true or it is true for all values of a. So when you think of all values of a A can either be greater than zero, they can either be equal to zero or a can either. Be a less than zero. Now, if a is positive, you and you take the square root of a positive number. You know that&#x27;s always defined. That&#x27;s always defined. That&#x27;s never gonna be incorrect but ends next step. If you say that a is equal to zero, you take the square root of zero. This is always true. Squared of zero is always zero, so this step is also true. So right now, what Sarah is saying works for a greater than our equal to zero. Now let&#x27;s take a look at a less than zero if A&#x27;s negative square root of a is undefined, so undefined. So the statement that a is equal to square with a touch where a is incorrect because a negative number cannot be something times another thing. You can&#x27;t have something squared equaling a negative number, and as a result, the values of a and don&#x27;t work is when a is less than zero. So, in a sense, Sarah is correct that it only works for value for some values. And the values that it works for is for values of a greater than zero. Assuming that A is an element of the real numbers and just to recap, we do agree with Sara&#x27;s. There is correct Skirt a R Squared A is an equal factor of a for some values of A and the values of A. That work is when a cz greater than or equal to zero. And that&#x27;s just to say again under the assumption that is a real value. Thanks for listening, guys hope this helps solve this problem. And I hope this helps with that theoretical understanding of square root of a negative number. Why that doesn&#x27;t work and why this doesn&#x27;t work for all values of a

Amy Jiang · Answer

So when we have a radical that doesn&#x27;t have a next, that is, we just have this notation here. Well, this means that we have an index of actually to this is square roots or are square roots function.

Bahar Tehranipoor · Answer

in this exercise, we have that X corpse, be ecstasy is a polynomial and that this person, Rita, is saying that we only have real roots when B squared is greater than or equal to four a. C. And so this is a true statement. We agree with what Rita is saying because we&#x27;re doing the quadratic formula and we have opposite B plus or minus the square root of B squared minus for a seat over to a That&#x27;s our route. So when we have the script on this for a C for this route to be riel, this has to be greater than equal zero. So you could say B squared minus for a C Square than or equal zero and tow ad for a suitable sides we end up at B squared is greater than or equal to four a. C. So if this is true, it means that our roots are riel. So it Rita saying, is indeed correct

Problem

a. Sarah said that in the set of real numbers, $\…

Problem 1 Medium Difficulty

Answer

$\sqrt[n]{k}=x^{n} o r-x^{n}$
$\sqrt[n]{k}=x^{n} : \sqrt[n]{-k}=-x^{n}$

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Ann Xavier Gantert

Algebra 2 and Trigonometry

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$\sqrt[n]{k}=x^{n} o r-x^{n}$$\sqrt[n]{k}=x^{n} : \sqrt[n]{-k}=-x^{n}$

Algebra 2 and Trigonometry

Ann Xavier GantertAlgebra 2 and Trigonometry

$\sqrt[n]{k}=x^{n} o r-x^{n}$
$\sqrt[n]{k}=x^{n} : \sqrt[n]{-k}=-x^{n}$

Ann Xavier Gantert

Algebra 2 and Trigonometry