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Problem 37 Easy Difficulty

A ladder 10 ft long rests against a vertical wall. Let $ \theta $ be the angle between the top of the ladder and the wall and let $ x $ be the distance from the bottom of the ladder to the wall. If the bottom of the ladder slides away from the wall, how fast does $ x $ change with respect to $ \theta $ when $ \theta = \pi/3? $

Answer

$\frac{d x}{d \theta}=5 \mathrm{ft} / \mathrm{Rad}$

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TE

Tsion E.

November 14, 2019

Isn't the ladder that's 10 feet long, not the vertical wall?

Video Transcript

the chancellor is the one. You right here. So, straw figure first you have a wall. Is this gonna be our ex con? Are Ladder is 10 feet. Is this gonna be data? So we see that data is going is opposite over high pot use. So sign data equals X over 10 we get 10. Sign Peeta equals X. We're gonna differentiate both sides. We got deep X over these data, which is equal to 10. Co sign data. We plug in pi thirds and this gives us five feet per red.