Question
A lambda hyperon $\Lambda^{0}$ (mass $=1115 \mathrm{MeV} / \mathrm{c}^{2}$ ) at rest decays into a neutron $n$ (mass $=940 \mathrm{MeV} / \mathrm{c}^{2}$ ) and a pion $\pi^{0}\left(\mathrm{mass}=135 \mathrm{MeV} / \mathrm{c}^{2}\right):$ $$\Lambda^{0} \rightarrow \mathrm{n}+\pi^{0}$$
Step 1
Step 1: The kinetic energy of the neutron is given by the equation $K = \Delta m c^2$, where $\Delta m$ is the mass difference between the initial and final particles, and $c$ is the speed of light. Show more…
Show all steps
Your feedback will help us improve your experience
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
A lambda hyperon $\Lambda^{0}$ (mass $=1115 \mathrm{MeV} / c^{2}$ ) at rest decays into a neutron $\mathrm{n}$ (mass $=940 \mathrm{MeV} / \mathrm{c}^{2}$ ) and a pion (mass $=135 \mathrm{MeV} / c^{2}$): $$\Lambda^{0} \rightarrow \mathrm{n}+\pi^{0}$$ What is the total kinetic energy of the neutron and pion?
A lambda hyperon $\Lambda^{\circ}\left(\right.$ mass $\left.=1115.7 \mathrm{MeV} / \mathrm{c}^{2}\right)$ at rest in the lab frame decays into a neutron $n$ (mass $=$ $939.6 \mathrm{MeV} / \mathrm{c}^{2}$ ) and a pion $\pi^{0}\left(\mathrm{mass}=135.0 \mathrm{MeV} / \mathrm{c}^{2}\right):$ $$ \Lambda^{0} \rightarrow n+\pi^{0} $$
A lambda hyperon $\Lambda^{0}\left(\mathrm{mass}=1115.7 \mathrm{MeV} / c^{2}\right)$ at rest in the lab frame decays into a neutron $\mathrm{n}$ (mass $=$ $939.6 \mathrm{MeV} / \mathrm{c}^{2}$ ) and a pion $\left(\mathrm{mass}=135.0 \mathrm{MeV} / \mathrm{c}^{2}\right)$ $$\Lambda^{0} \rightarrow \mathrm{n}+\pi^{0}$$ What are the kinetic energies (in the lab frame) of the neutron and pion after the decay? [Hint: Use Eq. (26- 11 ) to find momentum. ]
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD