00:01
Here in this given problem mass of the landing craft that has been given as m is equal to 1 .22 into 10 raised to the power 4 kilogram.
00:25
Altitude of this landing craft above the surface of planet that is given as h is equal to 5 .90 into 10 raised to the power 5 meter and time period that is 5800 seconds.
01:05
Radius of that planet r that will be equal to half of its diameter.
01:16
Diameter is given as 9 .50 into 10 raised to the power 6 meter.
01:21
So, its half that will be 4 .75 multiplied by 10 raised to the power 6 meter.
01:31
Suppose mass of the planet that is m p.
01:46
Hence using the concept that centripetal force for the motion of this landing craft means mv square by r, where small r is the radius of the orbit and that small r is actually r plus h.
02:06
So, mv square by r that will be given by using newton's law of gravitation.
02:11
Gravitational force between the craft and the planet that will be g.
02:16
G is universal gravitational constant multiplied by product of the masses of the two objects m into m p divided by r square.
02:25
So, cancelling this m mass of the craft, cancelling one of the r over here, we get an expression for the speed of the landing craft that is square root of g m p by r small r...