(a) The magnitude of the vector $\langle 12,0\rangle$ is $\sqrt{12^2 + 0^2} = \sqrt{144} = 12$.
(b) The magnitude of the vector $\langle 4,-5\rangle$ is $\sqrt{4^2 + (-5)^2} = \sqrt{16 + 25} = \sqrt{41}$.
(c) The magnitude of the vector $\langle 4,5\rangle$ is
Show more…