00:01
So to solve this question, we are going to use stephen buzmanlaw.
00:04
So for the part a, we are given that surface temperature is 450 degrees celsius.
00:10
So we must convert it to kelvin.
00:12
Let's convert it 450 plus 273.
00:16
It's 723 kelvin.
00:21
And the temperature of surrounding is 27 degrees celsius.
00:27
That is 300 kelvin.
00:31
And we are asked the rate at which energy is transferred by radiation so we'll use stephen boltzmann law sigma epsilon a times temperature of the body or the lava in this case to the four minus temperature of surrounding to the four we are given stephen bozeman constant which is 5 .67 times 10 power negative 8.
01:06
Epsilon is one because temperature is very high.
01:14
Since it's not given to us, we can safely assume that area is given to us as one meter square, 723 to the 4 minus 300 to 4.
01:31
Let's do this difference first.
01:39
So the answer here is 265 billion or it isn't finished yet.
01:49
We have to multiply it by 5 .67 times 10 power negative 8.
02:00
So the answer will be 15 ,000 and 34 joules per seconds.
02:13
So let's convert it.
02:17
Let's write it in terms of proper significant digits.
02:20
That is three significant digits.
02:22
So answer here will be q.
02:24
Divided by t is equal to 1 .5 times 10 power 4 1 .50 times 10 power 4 joules per seconds or what? answer given below the question is wrong.
02:43
So let's solve for the part b...