Question
A laser beam can be focussed on an area equal to the square of its wavelength. A He-Ne laser radiates energy at the rate of $1 \mathrm{nW}$ and its wavelength is $632.8 \mathrm{~nm}$. The intensity of focussed beam will be(A) $1.5 \times 10^{13} \mathrm{~W} / \mathrm{m}^{2}$(B) $2.5 \times 10^{9} \mathrm{~W} / \mathrm{m}^{2}$(C) $3.5 \times 10^{17} \mathrm{~W} / \mathrm{m}^{2}$(D) None of these
Step 1
Mathematically, this can be represented as: \[ A = λ^2 \] Given that the wavelength of the He-Ne laser is 632.8 nm, we can substitute this value into the equation: \[ A = (632.8 \times 10^{-9})^2 = 4 \times 10^{-13} \, m^2 \] Show more…
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A laser beam can be focussed on an area equal to the square of its wavelength A He-Ne laser radiates energy at the rate of 1mW and its wavelength is 632.8 nm. The intensity of focussed beam will be?
(a) How many photons are emitted per second by a He-Ne laser that emits $1.0 \mathrm{mW}$ of power at a wavelength $\lambda=632.8 \mathrm{nm} ?$ (b) What is the frequency of the electromagnetic waves emitted by a He-Ne laser?
Output power of He-Ne LASER of low energy is $1.00 \mathrm{~mW}$. Wavelength of the light is $632.8 \mathrm{~nm}$. What will be the number of photons emitted per second from this LASER? (A) $8.31 \times 10^{15} \mathrm{~s}^{-1}$ (B) $5.38 \times 10^{15} \mathrm{~s}^{-1}$ (C) $1.83 \times 10^{15} \mathrm{~s}^{-1}$ (D) $3.18 \times 10^{15} \mathrm{~s}^{-1}$
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