Question
A length $l$ of wire carries a steady current $i$. It is bent first to form a circular plane coil of one turn. The same length is now bent more sharply to give three loops of smaller radius. The magnetic field at the centre caused by the same current is(a) one-third of its value(b) unaltered(c) three times of its initial value(d) nine times of its initial value
Step 1
Step 1: The magnetic field at the center of a circular loop carrying current $i$ is given by $B = \frac{\mu_0 i}{2r}$, where $r$ is the radius of the loop and $\mu_0$ is the permeability of free space. Show more…
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A length of wire carries a steady current. It is bent first to form a circular coil of one turn. The same length is now bent more sharply to give a double loop of smaller radius. The magnetic field at the centre caused by the same current is (A) a quarter of its first value. (B) unaltered. (C) four times of its first value. (D) half of its first value.
A length L of wire carries a steady current $1 .$ It is bent first to form a coil of 1 turn. The same length is now bent more sharply to give a double loop of smaller radius. The magnetic field at the centre caused by the same current is (a) A quater of its first value (b) Un changed (c) Four times of its first value (d) A half of its first value
A wire carries a current. Maintaining the same current it is bent first to form a circular plane coil of one turn which produces a magnetic field B at the centre of the coil. The same length is now bent more sharply to give a double loop of smaller radius. The magnetic field at the centre of the double loop, caused by the same current is
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