00:01
In part a, we're asked to show that the relation on the set of functions from the positive managers to the positive managers, such that the pair f and g belongs to this relation, if and only f is big theta of g, is an equivalence relation.
00:24
So to prove this is an equivalence relation, let's prove it's reflexive.
00:32
So let f be a function from the positive managers to the positive managers.
00:50
And as f is large data, take k to be 1, then we have that for all x greater than k with c equal to 1, we have that c times the absolute value of f of x.
01:31
Well, this is simply going to be the absolute value of f of x.
01:34
So this is going to be less than or equal to the absolute value of f of x.
01:50
Clearly, this is going to be less than or equal to one times the absolute value of f of x, which is c times the absolute value of f of x.
02:00
So this implies that f is big theta of f, and therefore we have that relation to r is reflexive, since f is related to itself.
02:25
Now to prove the r is symmetric, we're going to, going to pose that pair fg is an r.
02:39
This means that f is big theta of g.
02:51
So then we have that for all x greater than k, for some non -zero constants, c1, c2, and k, we have that c1 times the absolute value of g of x, is less than or equal to absolute value of f of x, which is less than equal to c2 times the absolute value of g of x.
03:34
This is what being b theta of g means.
03:39
Now let's take c1 prime to be 1 over c1, and let's take c2 prime to be 1 over c2.
03:57
This is possible because c1 and c2 are both non -zero constants.
04:08
Then we have for all x greater than k by solving.
04:15
The above inequality, well, we have the absolute value of g of x over c1 prime is less than or equal to the absolute value of f of x, which is less than or equal to absolute value of g of x over c2 prime.
04:44
And so we have that, in other words, c1 prime, absolute type of x of x, is going to be less than or equal to absolute value of g of x, which is less than or equal to c2 prime times the absolute value of f of x.
05:35
Actually in reverse, we have, sorry, c2 prime times f of x.
05:40
This is going to be less than equal to g of x, which is less than or equal to c1 prime, f of x.
05:47
My mistake.
05:52
So by big theta notation, we have that g is big theta of f.
06:01
So if you're a big theta of f, follows that g is related to f and therefore that r is symmetric.
06:16
Now to prove that r is transitive, suppose that f and g are related and that g and h are related.
06:34
So this implies that f is big theta of g and we have that g is big theta of h...