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Problem 1 Problem 2 Problem 3 Problem 4 Problem 5 Problem 6 Problem 7 Problem 8 Problem 9 Problem 10 Problem 11 Problem 12 Problem 13 Problem 14 Problem 15 Problem 16 Problem 17 Problem 18 Problem 19 Problem 20 Problem 21 Problem 22 Problem 23 Problem 24 Problem 25 Problem 26 Problem 27 Problem 28 Problem 29 Problem 30 Problem 31 Problem 32 Problem 33 Problem 34 Problem 35 Problem 36 Problem 37 Problem 38 Problem 39 Problem 40 Problem 41 Problem 42 Problem 43 Problem 44 Problem 45 Problem 46 Problem 47 Problem 48 Problem 49 Problem 50 Problem 51 Problem 52 Problem 53 Problem 54 Problem 55 Problem 56 Problem 57 Problem 58 Problem 59 Problem 60 Problem 61 Problem 62 Problem 63 Problem 64 Problem 65 Problem 66 Problem 67 Problem 68 Problem 69 Problem 70 Problem 71 Problem 72 Problem 73 Problem 74 Problem 75 Problem 76 Problem 77 Problem 78 Problem 79 Problem 80 Problem 81 Problem 82 Problem 83 Problem 84

Problem 1 Easy Difficulty

A LiBr molecule oscillates with a frequency of $1.7 \times 10^{13}$ Hz. (a) What is the difference in energy in eV between allowed oscillator states? (b) What is the approximate value of $n$ for a state having an energy of 1.0 ev?

Answer

a) 0.07 $\mathrm{eV}$
b) 14

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Physics 103

College Physics for AP® Courses

Chapter 29

Introduction to Quantum Physics

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Video Transcript

in this problem, where Asa cock a difference and energy and electron volts between allowed oscillator states and then calculate the approximate value of end for having an energy of one electron volts. So to find the difference in the energy, you need to multiply planks Constant, which is represented by an h times the frequency which is given to us in the problem as 1.7 times tended the 13 so plans Constant comes in different values, but the one we're going to use here it's 4.14 times 10 to the negative 15 because it's asking for our final answer in electron volts, and our frequency is given as 1.7 times 10 to the 13th. And when you've multiplied those two values, then you get 0.7 electron volts and then to solve for the approximate value of N well. That could be determined using E equals and plus 1/2 where and is our unknown value here. And that's what we're trying to solve for times, planks, constant times frequency so we can get and by itself, by dividing bye plagues constant frequency and then subtracting in a 1/2 so that our final equation looks like e divided by planks. Constant times frequency minus 1/2 gives us an approximate value for it. And we want our energy in this case to be one electron volts. So again, one electron volts planks, constant frequency minus 1/2 gives us an N value of 13.7, which is approximately equal, so 14.

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