00:01
For this problem on the topic of geometric optics, we are told that a light ray enters the atmosphere of a planet and descends a distance of 20 kilometers vertically towards the surface.
00:11
The index of refraction at the point where the light enters the atmosphere is 1 and increases linearly to the surface where it has a value of 1 .005.
00:21
We want to know how long it takes the ray to travel this path, and we want to compare this time to the time it would take without an atmosphere.
00:31
Now we let nx be the index of refraction at a distance x below the top of the atmosphere, and at a distance h, we'll call this value n.
00:40
This is the value at the planet's surface.
00:43
So n as a function of x is equal to 1 plus n minus 1 over h times x.
00:59
And so the total time interval required to traverse the atmosphere, delta t, is the integral from 0 to h of d x over v, which for light is the integral from 0 to h of n as a function of x over c, d x.
01:26
And so this is equal to 1 over c times the integral from 0 to h of 1 plus n minus 1...