00:01
Let me draw the figure.
00:02
So this is the surface, right? and the light ray strikes this point.
00:16
It angle theta, and then it refracts towards the normal, right? and let's say this angle is theta 2.
00:28
And from here, this light goes in this direction.
00:33
And let's say this angle this angle is theta 3 now this angle is theta 2 this one is theta 2 right okay now let's do part a now we do part a well for the refracted ray to undergo a total internal reflection theta 3 shown in the figure must be larger than the critical angle.
01:17
So theta 3 must be greater than or equal to critical angle.
01:27
And let's say this is equation number one.
01:30
Well we know that critical angle sign of critical angle equals n2 divided by n1.
01:39
So critical angle equals sine inverse into n2 divided by n1 right and now by substituting values critical angle theta c is equal to sine inverse into 1 .0 divided by 1 .49 so critical angle theta c is equal to 42 .0 42 .0 sorry 40.
02:14
42 .2 degrees.
02:16
It's equal to 42 .2 degrees, right? now let's substitute this value in equation number one.
02:29
Then we have theta 3 is equal to or greater than 42 .2 degrees...