00:01
So we're told that we have a light rate traveling in air with an index of refraction i call n -sub -a that is incident on a prism, which has an index of refraction in sub -p of 1 .5.
00:12
Okay.
00:14
And we're told that this initial angle of incident theta is equal to 60 degrees.
00:19
Okay.
00:20
And we're asked to look at figure p22 .24 to follow the ray path as shown in the figure.
00:26
And it wants us to find angle fine made by the outgoing ray with the prism face there.
00:33
So using snell's law, we're going to start with the index of refraction of error times the sign of the incident angle, theta, is equal to index of refraction of prism times the sign of r, which is the angle of refraction there.
00:50
And we call this one little r in that photo.
00:52
Okay.
00:53
So then solving for r, we find that this is equal to.
00:56
The inverse sign of n sub a divided by n sub p multiplied by the sign of the angle theta, which we're told us 60 degrees.
01:14
So solving for this, we find that r is equal to 35 .26 degrees.
01:26
So that's the angle of that first refraction there...