A line having a total resistance of $0.20 \Omega$ delivers $10.00 \mathrm{~kW}$ at $250 \mathrm{~V}$ to a small factory. What is the efficiency of the transmission?The line dissipates power due to its resistance. Consequently we'll need to find the current in the line. Use $\mathrm{P}=V I$ to find $I=\mathrm{P} / V$. Then
Power lost in line $=I^{2} R=\left(\frac{\mathrm{P}}{V}\right)^{2} R=\left(\frac{10000 \mathrm{~W}}{250 \mathrm{~V}}\right)^{2}(0.20 \Omega)=0.32 \mathrm{~kW}$
$$
\text { Efficiency }=\frac{\text { Power delivered by line }}{\text { Power supplied to line }}=\frac{10.00 \mathrm{~kW}}{(10.00+0.32) \mathrm{kW}}=0.970=97.0 \%
$$