00:02
Okay, so we are given that the rate of draining is 1 .9 cubic centimeters per second.
00:08
This is the flow rate q in the tube.
00:12
Now let's calculate the velocity of the fluid in the tube.
00:14
The cross sectional area of the tube can be calculated using the formula a equal to pi times r squared where r is the radius of the tube.
00:22
Now we have r equal to 1 mm or we can say 0 .1 centimeter.
00:27
So putting the values we have area equal to pi times 0 .1 whole squared which is equal to 0 .0314 centimeter squared.
00:35
Now we can calculate the velocity of the fluid in the tube using the formula v equal to q over a.
00:43
When putting the values we have v equal to 1 .9 over 0 .0314 and that is equal to 60 .51 centimeter per second.
00:52
Now the reynolds number re is the dimensionless quantity that helps determine whether the flow is laminar or turbulent is given by the formula re equal to rho times v times t over mu.
01:06
Now we are given the specific gravity of the fluid 0 .95 which is the ratio of the fluid density to the density of water...