A liquid stands at the same level in the U-tube when at rest. If area of cross-section of both the limbs are equal, the difference in heights $h$ of the liquid in thetwo limbs of $U$-tube, when the system is given an acceleration $a$ in horizontal direction as shown, is
(A) $\frac{g L^{2}}{a H}$
(B) $\frac{L a}{g}$
(C) $\frac{L^{2} a}{H g}$
(D) $\frac{H g}{a}$