00:01
This item has three parts to it.
00:03
The first asks you to list all possible rational roots.
00:08
So let's go ahead and do that.
00:10
Recall that we need the factors of five divided by the factors of six.
00:17
So we'll go with positive negative.
00:21
One, five, the only factors of the final constant.
00:26
And one, two, three, six.
00:30
So when we populate a list, we have one over one, one over two, one over three, one over six.
00:44
We will have five over one, five over two, five over three, and five over six.
00:55
And interestingly enough, there is no duplication here.
00:59
We've got the value of one, one -a -half, one -third, a sixth, five, five over two, five over three, five over six.
01:10
There's no duplication.
01:11
So this set here of one, two, three, four, eight, sixteen values, because we have the positive negative, is the list of all possible rational roots.
01:24
The second part of this question asks you to use synthetic division to test the possible rational roots and find an actual root.
01:35
So let's go ahead, rather than start with all these fractions, let's go with the positive negative 1, positive negative 5.
01:43
I'll start with negative 1.
01:47
We set up a 6, 25, negative 24, and 5.
01:56
Drop the 6, multiplied by the negative 1, and add.
02:04
Multiply by the negative 1 and add.
02:08
I can tell already we are not going to have a 0 here.
02:15
43 and add.
02:18
Clearly this is not equal 0, so we have not found a root.
02:22
Let's try negative 5.
02:26
The same setup.
02:34
Drop the 6.
02:36
Negative 5 times 6, negative 30.
02:40
Gives us a negative 5.
02:43
Multiply 25.
02:45
1.
02:47
Hey, looks like we got one...